If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25

If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5.

3 : 5; 3 : 5 <==ANSWER

8 0

4 years ago

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Consider H0: μ = 45 versus H1: μ < 45. A random sample of 25 observations produced a sample mean of 41.8. Using α = .025 and

a_sh-v [17]

Given
$H0: \ \mu=45 \\ \\ H1: \ \mu\ \textless \ 45$
This is a one-tailed test.

$z= \frac{41.8-45}{6/ \sqrt{25} } = \frac{-3.2}{6/5} = \frac{-3.2}{1.2} =-2.6667$

$P(z\ \textless \ -2.6667)=0.00383$

Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.

5 0

3 years ago

Find the area of the figure shown

allsm [11]

Its 23 all you have to do is times all the numbers around

5 0

3 years ago

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