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2 years ago

Simplify this expression using the properties of powers

Mathematics

2 answers:

statuscvo [17]2 years ago

5 0

2h to the 6th power!!

alina1380 [7]2 years ago

4 0

2 to the 6th power is the correct one

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An additional amount of money added to borrowed money only on principal is what kind

Snowcat [4.5K]

Answer:

simple interest

Step-by-step explanation:

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2 years ago

Helpppppppppppppppppppppppppppp me

dalvyx [7]

I believe it's the last one

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2 years ago

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

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3 years ago

Helppp!!!<br> Simplify this. Please explain it too.<br><br> 18x^4 – 3x^3 – 2x^3 + x^2 – 10 + 6

strojnjashka [21]

Answer: 18x^4 - 5x^3 + x^2 - 4

Step-by-step explanation:

We need to add like terms.

-10 and 6 are like terms

-10 + 6 = - 4

-3x^3 and -2^3 are like terms

-3x^3 + -2^3 = -5x^3

There are no other like terms.

18x^4 - 5x^3 + x^2 - 4

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3 years ago

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chubhunter [2.5K]

area = 7×2+7×2+11×2 = 50sq ft

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2 years ago