Answer:
range = 7.87
X = 62.12, X²= 164.3516
mean = 1.2424
variance = 1.779
standard deviation = 1.33379
coefficient of variation = 107.3559%
Step-by-step explanation:
a.) The range =
highest number - lowest number
= 7.89 - 0.02
= 7.87
b.) from the attachment I solved for X and X²
∑X = 62.12
∑X² = 164.3516
c.)
the mean = ∑x/n
n = 50
= 62.12/50
= 1.2424
variance =
σ² = [∑x²-(∑x)²/n] / n-1
= [164.3516 - (62.12)²/50] / 50-1
= 164.3516 - 77.17788/49
= 87.173712/49
= 1.779
standard deviation = √σ
= √1.779
= 1.33379
d. coefficient of variation
= σ/mean * 100
= 1.33379/1.2424 * 100
= 107.3559
This number tells us that the the standard deviation of the time to failure is larger than the average time. option 3 is the correc4 answer here
Answer:
x^3+9x^2-3x^2-3
Step-by-step explanation:
You can use a various of methods but when you use the box method you multiply each separately.
Like you would multiply x² by x, 8x by x, -3 by x (thats the first row)
x² by 1, 8x by 1, -3 by 1 ( for the second row)
Then you get those final variables and combine like terms getting the answer above
Answer:
1 Hour
250 + 150h = 500
Step-by-step explanation:
So, the fee for the meeting is 250. The hourly fee is 150. Let h equal the number of hours.
250 + 150h
If pablo has 500, then we cannot exceed that amount. So, our equation becomes
250 + 150h = 500
Subtract 250 from both sides
150h = 250
And divide by 50 on both sides. You get x = about 1.67. Since this is a question about time and money, you would round down to 1.
The gradient is the direction of steepest ascent. 5 is the coefficient of x, <span>y=mx+c,</span> so 5 is the gradient to this algebraic equation.<span />
Answer:
The approximate number of years until the species is extinct will be 9 years
Step-by-step explanation:
We are given
The population of a species is modeled by the equation
where
t is the number of years
we have to find time when species extinct
we know that any species will be extinct only if population of that species becomes 0
so, we can set P(t)=0
and then we can solve for t
we can factor it
we get t value as imaginary for this equation
So,
the approximate number of years until the species is extinct will be 9 years
