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Firdavs [7]
3 years ago
13

Answer......................................

Mathematics
2 answers:
Lina20 [59]3 years ago
7 0

hello :D..................

pickupchik [31]3 years ago
6 0
The photo is blurry can you repost so I can help?
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PLEASE HELP ASAP!!!!
Paul [167]

Answer:

the answers are <u>B and D </u>

Step-by-step explanation:

please let me know if I am wrong

I found about the answers by determine bias questions from non bias questions.

6 0
4 years ago
In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen
Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type            ni                xi                  si

Graded       42           0.486            0.187

No-fines      42           0.359           0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}}  + \frac{s_{2}^{2} }{n_{2}} } }

Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42}  + \frac{0.02496 }{42} } }

Z = \frac{0.127 }{\sqrt{0.001468}}

Z = \frac{0.127 }{0.0377}

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0
3 years ago
What number can be removed from the following list of data so that the median will the remain the same? 45, 20, 21, 35, 15, 29,
PSYCHO15rus [73]
35 is the number you can remove so you can still have the same median
4 0
4 years ago
Use properties of operations to write two equivalent expressions for 13(4 + x).
lesantik [10]

Answer:

13(4+x)

=52+13x

Step-by-step explanation:

13 multiplies the 4 and x.

then 13 multiply 4 is 52 while 13 multiply x 13x.

6 0
3 years ago
HELP ME PLEASE!!! THANK YOU!
AURORKA [14]

Answer:

down v

Step-by-step explanation:

1=20 mph

2=40 mph

3 1/4= 60.5 mph(im not sure if its correct but.)

.5 mph=10

2.5 mph=50

thats all i know

3 0
3 years ago
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