Answer:
Human activities commonly affect the distri-
bution, quantity, and chemical quality of water
resources. The range in human activities that affect
the interaction of ground water and surface water is
broad.Explanation:
Answer:
a) S = 2.35 10³ J/m²2
,
b)and the tape recorder must be in the positive Z-axis direction.
the answer is 5
c) the direction of the positive x axis
Explanation:
a) The Poynting vector or intensity of an electromagnetic wave is
S = 1 /μ₀ E x B
if we use that the fields are in phase
B = E / c
we substitute
S = E² /μ₀ c
let's calculate
s = 941 2 / (4π 10⁻⁷ 3 10⁸)
S = 2.35 10³ J/m²2
b) the two fields are perpendicular to each other and in the direction of propagation of the radiation
In this case, the electro field is in the y direction and the wave propagates in the ax direction, so the magnetic cap must be in the y-axis direction, and the tape recorder must be in the positive Z-axis direction.
the answer is 5
C) The poynting electrode has the direction of the electric field, by which or which should be in the direction of the positive x axis
Y no me han dicho que me ha dado un teléfono y me ha dicho la policía que han dado la cara para la que ha sido un policía que han dicho nada que no se han dado cuenta de
Answer: 3 seconds
Explanation:
Initial velocity(u) of projectile A in vertical direction = 0m/s
acceleration due to gravity a=g=9.81m/s^2
Time taken(t) of projectile A = 3s
Initial velocity of projectile B = 0m/s(vertical direction)
We can get height of cliff using parameters of projectile A since it's the same location.
Height(S) = u×t + 0.5×a×t^2
u =0
S= 0.5×9.81×3^2 = 44.145m
Time taken for projectile B to reach the ground:
S = u×t + 0.5×a×t^2
u =0, S=44.145m, a=9.81m/s^2
44.145 = 0.5×9.81×t^2
44.145 = 4.905×t^2
44.145 ÷ 4.905 = t^2
9 = t^2
t = sqrt(9)
t = 3seconds
Answer: The velocity with which the sand throw is 24.2 m/s.
Explanation:
Explanation:
acceleration due to gravity, a = 3.9 m/s2
height, h = 75 m
final velocity, v = 0
Let the initial velocity at the time of throw is u.
Use third equation of motion
The velocity with which the sand throw is 24.2 m/s.
