3 years ago

QUESTION 5

Physics

1 answer:

liberstina [14]3 years ago

5 0

Answer:

0.69 g/cm^3

Explanation:

Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.

The volume of the frog will be:

79 - 50 = 29mL

Convert it to litre by dividing it by 1000

29/1000 = 0.029 L

Since 1L = 1000 cm^3

Convert it to cm^3 by multiplying it by 1000

0.029 × 1000 = 29 cm^3

Density = mass/volume

Substitute the mass and volume into the formula

Density = 20/29

Density = 0.6896 g/cm3

Therefore, the density of the frog is 0.69 g/cm^3 approximately

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A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical

iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

$T = 2 \pi \sqrt{\frac{m}{k} } \\$

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

$T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m$