Answer:

Explanation:
First of all, let's convert from nanometres to metres, keeping in mind that

So we have:

Now we can convert from metres to centimetres, keeping in mind that

So, we find:

I will try to name as much as I can :
• Magnets
• Butter
• Petroleum
• Using a spherical object leaves the surface with very little surface area, basically using balls will help alot
• Using a hockey table leaves you with not friction at all when on
The Atwood's machine is in motion starting from rest, then Vf = Vo + a(t).
<span>Final Velocity is given as 6.7 m/s and the time is 1.9 s thus 6.7= 0+ a(1.9) </span>
<span>then a = 6.7/1.9 = 3.526 m/s². </span>
<span>The Atwood's Machine also has the formula d= distance = 1/2a(t²) </span>
<span>distance given is 6.365 m , then 6.365 = 1/2 a (1.9)², </span>
<span>a = 3.526 m/s² the same acceleration. </span>
<span>a= g(m1-m2) / m1+m2) </span>
<span>m1a + m2a = m1g - m2g </span>
<span>m1a - m1g = -m2g - m2a </span>
<span>3.526 m1 - 9.81 m1 = -9.81m2 - 3.526 m2 </span>
<span>-6.28 m1 = -13.34 m2 </span>
<span>0.47 m1= m2 </span>
<span>if 24J = 1/2mv² </span>
<span>then 24J = 1/2 m1 ( 6.7)² </span>
<span>48/ 44.89 = m1 </span>
<span>1.069 kg = m1 , then </span>
<span>0.47(1.069) = m2 </span>
<span>0.503 kg = m2</span>
The friction between the tires and the road causes loss of energy in the form of heat-energy.
<h3>What is kinetic energy?</h3>
The term kinetic energy refers to the energy of an object that is in motion. The pasengers that are sitting at a point possess potential energy. If the bus stops suddenly, the potential energy of the passengers is converted to kinetic energy as they move forward.
Since friction causes loss of energy, the friction between the tires and the road causes looss of energy in the form of heat-energy.
Learn more about kinetic energy: brainly.com/question/12669551
Answer:
Velocity will be 
Explanation:
We have given magnetic field B = 0.00005 T
Mass m = 238 U
We know that 
So 238 U 
Radius 
We know that magnetic force is given by
which is equal to the centripetal force
So 

