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3 years ago

Zane has 30 cupcakes and wants to give six each to a number of his friends.How many friends can he do this for ?

Mathematics

2 answers:

choli [55]3 years ago

7 0

5 friends this one was pretty easy

Nostrana [21]3 years ago

6 0

The answer is 5 because if you do the math 30 divided by 6 it equals 5

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30 points

Debora [2.8K]

Well what is 30x3 (because that is how you would find what is one third of unknown) then you find the answer witch is 90$

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2 years ago

if it is p miles from home to school how many round trips can be made if your car gets q miles per gallon of gasoline and there

Bumek [7]

5 is less than or equal to (2q)/p

3 0

2 years ago

Please Help Me!!!!!! I have a big test tomorrow!!!!!!!! I will give 30 points!!!!!!!!! The expression represents the number of m

il63 [147K]

Answer:

For this expression I guessed I would use subtraction because when you subtract Kimiko's miles to Celeste's miles you could see how much faster Kimiko was than Celeste.

Step-by-step explanation:

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2 years ago

Is 3/10 greater than 5/10

storchak [24]

3 of anything is almost always less than 5 of the same thing.
That's true for cows, rocks, trees, fish, salt-shakers, and babies.
I can't think of any object where it wouldn't be true.
Why wouldn't it be true for tenths ?

Let me say it another way:

No. 3/10 is <em>less than</em> 5/10 .

3 0

3 years ago

Read 2 more answers

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

Zane has 30 cupcakes and wants to give six each to a number of his friends.How many friends can he do this for ? ​

Zane has 30 cupcakes and wants to give six each to a number of his friends.How many friends can he do this for ?