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alukav5142 [94]
3 years ago
6

This year, Benny is 12 years old, and his mom is 48 years old.

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0
A. 12/48 = .25 = 25%

b. 48/12 = 4 = 400%

c. 50/14 = 3.57 = 357%

d. 58/22 = 2.67 = 267%

e. 2x = x+36
    x = 36
    36-12 = 24 years

f. I disagree. Benny is not aging any faster than his mother. They will always be 36 years apart.
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The diameter d of a sphere is twice the radius r. The volume of the sphere as a function of its radius is given by v(r)= 4/3(3.4
g100num [7]

Answer:

The diameter d of the sphere as a function of the radius is given by

d(r) = 2\times r

Step-by-step explanation:

Given:

The volume of the sphere as a function of its radius is given by

v(r)= \frac{4}{3}\times (3.14)(r)^{3}

Function:

A function is like a machine that gives an output for a given input.

A function has an independent variable which is called the input of the function.

The output for a given input is called the dependent variable.

Here. 'r' is the radius of a sphere independent variable

d(r) is the function dependent variable i.e Diameter as a function of radius as an output.

∴ d ( r )  = 2 r

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3 years ago
A water hose cost 3.60 per metre. Sam buys a 4.5 m long hose. how much does sam pay?
Mashutka [201]

Answer:

This will cost $16.20. $3.60*$4.5=$16.20

Step-by-step explanation:

8 0
4 years ago
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Negative one times the sum of twice a number and 3 is equal to 2 times the
den301095 [7]
Lets just say the number is equal to x.
-1(2x+3)=2*(-4x-3)
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3 0
3 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
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valentinak56 [21]

Answer:

I think it goes like this:

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Step-by-step explanation:

3 0
3 years ago
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