This year, Benny is 12 years old, and his mom is 48 years old.

1 answer:

4 0

A. 12/48 = .25 = 25%

b. 48/12 = 4 = 400%

c. 50/14 = 3.57 = 357%

d. 58/22 = 2.67 = 267%

e. 2x = x+36
x = 36
36-12 = 24 years

f. I disagree. Benny is not aging any faster than his mother. They will always be 36 years apart.

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If a circular property has a diameter of 50' and costs $120 per square foot, what is the cost of the property?

dusya [7]

Find area
area=pir^2
d/2=r=50/2=25

A=pi25^2
a=pi625
aprox pi=3.141592
a=1963.495
that is how many square feet
multiply that by 120
1963.495 times 120=$235,619.4

5 0

2 years ago

(a) Use a linear approximation to estimate f(0.9) and f(1.1). f(0.9) ≈ f(1.1) ≈ (b) Are your estimates in part (a) too large or

olasank [31]

Answer:

(Missing part of the question is attached)

$L(x)=2x+3$

Estimates are too large.

Step-by-step explanation:

Suppose the only information we know about the function is:

$f(1)=5$

where the graph of its derivative is shown in the attachment

If the function $f\\$ is differentiable at point $x=1$ , the tangent line to the graph of $f$ at 1 is given by the equation:

$y=f(1) +f'(1)(x-1)$

So we call the linear function:

$L(x)=f(1) +f'(1)(x-1)$

We know the $f(1)=5$ as it is given in the question, and $f'(1)=2$ from the graph attached. Substitute in the equation of $L(x)$ .

$L(x)=5+2(x-1)\\L(x)=5+2x-2\\L(x)=2x+3\\$

At x=1, $f'(x)$ is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve $f$ . Thus, The estimates are too large.