The answer is D.
|-4| < 4
4 < 4
|-1| < 0
1 < 0
|-6| = -6
6 = -6
|-14| > 10
14 > 10
If I have at least 50 of something, that means I have 50, 51, 52, etc...
v - 1 ≥ 13
Hope this help
The answer is has to be D
The product of denominators can always serve as the common denominator. The appropriate choice is ...
... z times u . . . . . . . the first choice
P(boy's name) = 16/30 = 0.53 (the three's continuous) = 53.3%