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xz_007 [3.2K]
2 years ago
12

A home-decorating company is determining the amount of fabric required for a customer's window treatments. A single window requi

res 12 2/3 yards and a double window requires 17 5/6 yards of fabric. If there are two single windows and one double window, how much fabric is required?
Mathematics
1 answer:
Julli [10]2 years ago
6 0

Answer:

43\frac{1}{6} \:yards

Step-by-step explanation:

<u>GIVEN :-</u>

Amount of fabric required for :-

  • a single window = 12\frac{2}{3} = \frac{38}{3}  \:yards
  • a double window = 17\frac{5}{6} = \frac{107}{6} \: yards

<u>TO FIND :-</u>

Amount of fabric required for two single windows and one double windows.

<u>SOLUTION :-</u>

Amount of fabric required for two single windows = 2(\frac{38}{3} ) = \frac{76}{3} \:yards

Amount of fabric required for 2 single & 1 double window =  \frac{76}{3} + \frac{107}{6}

                                                                                                =  \frac{152+107}{6}

                                                                                                =   \frac{259}{6}

                                                                                                =  43\frac{1}{6} \:yards

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We will have numbers 1,2,3,4. So total 4 integers for this one

Case2: All 2-digit numbers

We can fill 1 digit place in 4 ways ( can choose any number out of 1,2,3,4). Then again we can fill 2nd digit place in 4 ways ( can choose any number out of 1,2,3,4). So all together we will have 4 × 4 = 16 integers for this one

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We can fill 1 digit place in 4 ways ( can choose any number out of 1,2,3,4). Then again we can fill 2nd digit place in 4 ways ( can choose any number out of 1,2,3,4). similarly we can fill 3rd digit place in 4 ways (again any number out of 1,2,3,4). So all together we will have 4 × 4 × 4 = 64 integers for this one.

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Again we can fill 1st digit place in 4 ways, then 2nd digit place in 4 ways, 3rd digit place in 4 ways, 4th digit place in 4 ways. So all together there will be 4 × 4 × 4 × 4 = 256 integers for this one.

Case5: All 5-digit numbers

Again we can fill 1st digit place in 4 ways, then 2nd digit place in 4 ways, 3rd digit place in 4 ways, 4th digit place in 4 ways, 5th digit place also in 4 ways. So all together there will be 4 × 4 × 4 × 4 × 4 = 1024 integers for this one

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So thats the final answer

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3 years ago
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