| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
40. 24+26=50 41. I don't understand that one either what grade are you in?
Answer:
The linear speed in which Darlene is traveling is 24.74 miles per hour.
Step-by-step explanation:
The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed (
), measured in inches per second, is defined by following expression:
(1)
Where:
- Radius of the wheel, measured in inches.
- Angular speed, measured in radians per second.
If we know that
and
, then the linear speed, measured in miles per hour, in which Darlene is traveling is:


The linear speed in which Darlene is traveling is 24.74 miles per hour.
Answer:
The approximate solution to the system is (1.2, 4.4)
x = 1.2 and y = 4.4
Step-by-step explanation:
The solution of the system of linear equations equation y = –0.25x + 4.7 and y = 4.9x – 1.64 is shown in the attached graph. The red line represents the equation y = –0.25x + 4.7 and the blue line represents the equation = 4.9x – 1.64.
The solution of the system of equations is their point of intersection shown on the graph.
The point of intersection is (1.231, 4.392). To the nearest tenth, it is (1.2, 4,4). So x = 1.2 and y = 4.4.
So the approximate solution to the system is (1.2, 4.4)