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lana [24]
3 years ago
11

Jenna is putting a ribbon around the border of a square frame. The area of the frame is 196 square inches. How long will the rib

bon need to be in order to go around the whole frame?
Mathematics
1 answer:
ehidna [41]3 years ago
8 0

Answer: 56 inches

Step-by-step explanation:

Given that:

Area of square frame = 196 in²

Area of a square = a²

Where a = side length

Hence side length (a) of the square :

a² = 196

a = √196

a = 14

To find the length of the ribbon required :

Find the perimeter of the square :

Perimeter of a square = 4a

= 4 * 14

= 56 inches

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Suppose you drop a ball from 120 feet. The ball will bounce to 25 of its previous height. What is the total distance the ball tr
tamaranim1 [39]

Answer:

277.1 feets

Step-by-step explanation:

Drop height = 120 feets

Ball bounces 2/5 of previous height

Height after 1st bounce :

120 * 2/5 = 48 feets

Return distance = 48 feets

Height after second bounce :

48 * (2/5) = 19.2 feets

Return distance = 19.2 feets

Height after 3rd bounce :

19.2 * (2/5) = 7.68 feets

Return distance = 7.68 feets

Height after 4th bounce :

7.68 * (2/5) = 3.072 feets

Return distance = 3.072 feets

Height after 5th bounce :

3.072 * (2/5) = 1.2288 feets

(120 + (2*48) + (2*19.2) + (2*7.68) + (2*3.072) + 1.2288) = 277.1328

= 277.1 feets

6 0
3 years ago
(3)<br>(7<br>2 cm<br>4 cm<br>4 cm<br>8 cm<br>Perimeter:<br>Area:​
pickupchik [31]

Answer:

the perimeter of 2cm 4cm 4cm and 8cm is 18...the area is 256

Step-by-step explanation:

7 0
3 years ago
Solve each of the following systems using the linear combination method. Check your answers
Dvinal [7]
3x+5y=11 answer : 3x+5y-11=0

Step by step explanation:

3x+5y=11
Move the constant to the left

3x+5y-11=11-11
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3x+5y=11

5y+8y
8 0
3 years ago
What is the value of x?<br> 30°<br> 130<br> to
Shalnov [3]

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Step-by-step explanation:

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B is the midpoint of AC, E is the midpoint of BD. If A(-9,-4), C(-1,6), and E(-4,-3), find the coordinates of D
Vadim26 [7]

Answer:

(-3, -7)

Step-by-step explanation:

Let (x_{A,}y_{A}),(x_{B},y_{B}),(x_{C,}y_{C}),(x_{D,}y_{D})(x_{E,}y_{E)} \text{be the coordinates of points A, B, C respectively}\\\\

The midpoint coordinates (x_{M},y_{M}) of any two points (x_{1},y_{1}) and (x_{2},y_{2}) are given by x_{M}=\frac{(x_{1}+x_{2)}}{2} and y_{M}=\frac{y_{1}+y_{2}}{2}

Since B is the midpoint of AC

x_{B}=\frac{(x_{A}+x_{C})}{2}=\frac{(-9+(-1)}{2}=\frac{-9-1}{2}=\frac{-10}{2}=-5

y_{B}=\frac{(y_{A}+y_{C})}{2}=\frac{(-4+6)}{2}=\frac{2}{2}=1

Since E is the midpoint of B and D and we are given the coordinates of E as (-4,-3). it follows that

x_{E}=\frac{x_{B}+x_{D}}{2} = \frac{-4+x_{D}}{2}

Therefore

x_{D}=2x_{E}+4=2(-5)+4=-3

Similarly

y_{E}=\frac{y_{B}+y_{D}}{2} = \frac{1+x_{D}}{2}y_{D}=2y_{E}-1=2(-3)-7=-7

8 0
2 years ago
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