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4 years ago

HELP!!! you dont have to answer all the questions at least the first one!!!

Mathematics

1 answer:

UkoKoshka [18]4 years ago

7 0

57/19 = 3
x^5 / x^2 = x^(5-2) = <span>x^3

so </span><span>57x^5 / 19x^2 = 3x^3

answer
</span>3x^3

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What is the condition on the probability of success p that will guarantee the histogram of a binomial distribution is symmetrica

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Answer:

The probability of success is 1/2.

Step-by-step explanation:

The histogram of a binomial distribution has a mode of n×p. For that to be n/2, the value of p must be 1/2.

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4 years ago

What is another way to write 3 x (4 +7)?

MakcuM [25]

Another way to write this is 3(4+7)

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3 years ago

Name the property of real numers illustrated by each equation. 16+(-13)=-13+16

AleksandrR [38]

Answer: Commutative property of addition

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3 years ago

EASY TRIG - 15 POINTS

poizon [28]

Answer: The answers are (a) 40 cm and (b) $\sin^{-1}\dfrac{23}{62}.$

Step-by-step explanation: The calculations are as follows:

(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.

Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have

∠BAC = ∠BDC = 30°.

Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.

We can write

$\sin \angle BDC=\dfrac{BC}{DC}\\\\\\ \Rightarrow \sin 30^\circ=\dfrac{20}{DC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{20}{DC}\\\\\\\Rightarrow DC=40.$

Thus, the diameter of the circle = 40 cm.

(b) See the figure (b).

As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.

Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have

∠EGF = ∠EDF = ?

Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.

We can write

$\sin \angle EGF=\dfrac{EF}{GF}\\\\\\ \Rightarrow \sin \angle EGF=\dfrac{4.6}{12.4}\\\\\\\Rightarrow \sin \angle EGF=\dfrac{23}{62}\\\\\\\Rightarrow \angle EGF=\sin^{-1}\dfrac{23}{62}.$

Thus,

$\angle EDF=\angle EGF=\sin^{-1}\dfrac{23}{62}.$

4 0

3 years ago

The cost , c(x), for a taxi ride was given by c(x) =2×+4.00, where x is the number of minutes. What does the slope mean for this

Readme [11.4K]

Hi,

c(x) is a linear function, if you graph it, you obtain a straight line.

The slope is the coefficient of x, therefore the slope is 2.

When the ride starts (x = 0), the start cost is 4 dollars (or whatever the currency is), then every minute spent on the moving taxi, as many as 2 dollars need to be paid to taxi driver.

I hope these help.

Green eyes.

4 0

3 years ago