By using proportions, We expect 150 defects out of the 10,000 cars if the 3 defects out of the 200 cars sampled is representative of all 10,000 cars.
Option A is correct.
First, let's set up the proportions.
A proportion is an equation in which two ratios are set equal to each other.
We have 3/200 cars with defects and we want to know X for X/10000.
So 3/200 = X/10000
Now solve for X.
3/200 = X/10000
X = 
X = 150
So the answer is: We expect 150 defects out of the 10,000 cars if the 3 defects out of the 200 cars sampled is representative of all 10,000 cars.
Option A is correct.
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Answer:
It is 6%, as 360 is earned each year.
Step-by-step explanation:
If you're just looking for the simplified equation that would be : 5t + 28 = 6t - 34
But if you're looking to find the value of "t" that would be : t = 62
If then, you are looking for the answer to the equation with t inserted, the equations are equal both sides equal : 338
I hope that answered your question. If not, lmk.
Answer:
D) (0, -3)
Step-by-step explanation:
The solution of two linear equations is the point of intersection of their graphs.
From the graph, the point of intersection of the graphs of the two linear equations is on the y-axis. So, the 
value on the 
axis is always 0. Also, the point is below the x-axis. So, the value of the point will be negative.
From the choices given, only (0,-3) matches the above conditions.
Therefore, the correct choice is D. (0, -3).
Answer:
Step-by-step explanation:
The function s(x)=0.9(.82)^x models the number of subscription in tens of thousands where x represents the number of years since the trend has been observed.
s(x) represents the number of subscriptions to the Dorchester Daily in a given year.
0.9 in ten thousands represents the initial number of subscriptions to the Dorchester Daily in a given year.
0.82 represents the rate at which the number of number of subscriptions to the Dorchester Daily is declining. The rate in percentage is 100 - 82 = 12% each year.
x represents the number of years since the trend has been observed.
