Let's begin by putting together some equations:
Seth has charges $39 and then $13 per hour. Since "hour" is our variable, let's write that as $13h where h = the number of hours.
Seth = 39 + 13h, $39 plus $13 times the number of hours
Malcolm charges $55 and then $11 per hour. So:
Malcolm = 55 + 11h, $55 plus $11 times the number of hours
Our goal is to find out how many hours both have to work before they charge the same amount. So let's set our Seth and Malcolm equations equal to one another.
39 + 13h = 55 + 11h, because we want to solve for h to see the number of hours.
First let's subtract 39 from each side:
(39 + 13h) - 39 = (55 + 11h) - 39
13h = 16 + 11h
Now let's subtract 11h from each side:
(13h) - 11h = (16 + 11h) - 11h
2h = 16
Simplify and solve for h by dividing each side by two:
(2h)/2 = (16)/2
h = 8
So Malcolm and Seth would have to work for 8 hours before both earn the same amount. After 8 hours, Seth would earn more than Malcolm. Before 8 hours, Malcolm would earn more than Seth.
Do you have the whole question? The problem that you gave does not have a problem....
Either way, he still has to pay his 835.90. the additional fee is 5 per day and he does'nt pay the rest in 3 days so thats $15.
$835.90 + 15 = $850.90
"4x + 6 = 94" is the equation among the following choices given in the question that could be used to solve the problem. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that you were looking for and it has actually come to your help.
