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Illusion [34]
3 years ago
6

Please help, basic algebra. Find the value of x

Mathematics
1 answer:
Helga [31]3 years ago
7 0

Answer:  x = 131

Reasoning: Alternate interior angle theorem

The angles shown are inside the parallel lines, so they are interior angles. They are also considered alternate angles because they are on alternating sides of the transversal cut. Alternate interior angles are congruent when we have parallel lines like this.

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Solve for e.<br><br> 4/3=-6e-5/3
cricket20 [7]

Answer:

e = 1/2

Step-by-step explanation:

to solve foe e in  this 4/3=-6e-5/3

solution

4/3=-6e-5/3

4/3 + 5/3 = 6e

find the lcm of the left hand side

4 + 5/3 = 6e

9/3 = 6e

cross multiply

3 x 6e = 9 x 1

18e = 9

divide both sides by the coefficient of e which is 18

18e /18 = 9/18

e = 1/2

therefore the value of e in the expression above is evaluated to be equals to 1/2

5 0
3 years ago
Determine the scale factor for triangle abc to triangle ab^ prime c^ prime a 20 ft 10 2 b. 10 c. 20 1/2
Sergio [31]

Answer: 2

Step-by-step explanation:

4 0
2 years ago
ILL MARK BRAINILEST !! 80 POINTS
mixas84 [53]

\\ \rm\rightarrowtail y=x^2-10x+16

\\ \rm\rightarrowtail y=x^2-10x+16+9-9

\\ \rm\rightarrowtail y=x^2-10x+25-9

\\ \rm\rightarrowtail y=(x-5)^2-9

Vertex form

  • y=a(x-h)^2+k

So

vertex:-

  • (h,k)=(5,-9)
6 0
2 years ago
In △ABC, ∠C is a right angle and sinB=725.
scoundrel [369]

9514 1404 393

Answer:

  A  7/25

Step-by-step explanation:

The cosine of an angle is equal to the sine of its complement. In a right triangle, angle A is the complement of angle B. So, ...

  cos(A) = sin(B)

  cos(A) = 7/25

8 0
2 years ago
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
Read 2 more answers
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