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Rus_ich [418]
2 years ago
7

Help me to the this question​

Mathematics
1 answer:
lions [1.4K]2 years ago
8 0

Across

1 compass

2 shape

4 two pi to one

6 Pie x radius squared

8. arc

10 Point

11 radius

12 circumference

down

1 Chord

4major arc

5 Radii

7 degrees

9.circle

13 equidistant

hope this helps

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Solve (26/57)=(849/5x)
Gnesinka [82]
<span>Cross multiply 26*5x = 849 * 57 130 x = 48393 x = 48393 / 130 x = 372.25</span>
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The figure below is the graph of the dimensions of a rectangle whose adjacent side lengths exhibit inverse variation.
cricket20 [7]

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The answer is true just answered

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Solve for A in the equation AB + CD + EFG = Z.
Semenov [28]

Answer:

A =  (Z-CD - EFG)/B

Step-by-step explanation:

AB + CD + EFG = Z.

Subtract CD and EFG from each side

AB + CD + EFG-CD -EFG = Z-CD - EFG

AB  = Z-CD - EFG

Divide each side by B

AB /B = (Z-CD - EFG)/B

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3 years ago
Which best expression is the best estimate of the product of 7/8 and 8 1/10
Mars2501 [29]

Answer:

D. 1x8

Step-by-step explanation:

7/8 rounded is 1. And 8 and 1/10 rounder is 8, so therefore your answer is 1x8.

hope this helps! :)

7 0
3 years ago
Calculate the area of the regular pentagon below: A regular pentagon with side length of 11.8 inches and dotted line from center
vlada-n [284]

Answer:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

we know a regular polygon divides into 5 congruent triangles.

Side of pentagon i.e base of one triangle is 11.8 inches.

Also, distance from center to middle of side which is height of triangle is 8.1 inches.

Area of 1 triangle= \frac{1}{2}\times base\times height

                           =  \frac{1}{2}\times 11.8\times 8.1

                           = 47.79 sq inches.

Area of regular pentagon=area of 5 congruent triangles= 5\times 47.79=238.95 sq inches.

5 0
3 years ago
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