Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are 

. We can write these sequentially as 

 where 

.
So the integral is approximately

Recall that



so our sum becomes

 
 
        
        
        
(5,4)
x=5
y=4
hope this helped
mark brainliest   :)
you question did not make sense so i assumed this is what you meant and needed.
 
        
             
        
        
        
5/4
(15/16)(4/3) The 4/3 is the reciprocal of 3/4
=5/4
 
        
             
        
        
        
3 in 350 is 300 the 3 in 403 is 3