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3 years ago

‼️ANSWER QUICKLY THIS IS A TIMED TEST ‼️The community garden in your neighborhood has three

Mathematics

1 answer:

wariber [46]3 years ago

3 0

I’m not 100% sure but I think it’s 80

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3. What is the surface area of the triangular prism shown below?

jekas [21]

Answer:

1233cm^2

Step-by-step explanation:

a of triangle = 1/2 bh

1/2 x 12 x 9 = 54

108 x 2 = 108

a of regtangle = l x w

25 x 15 = 375

375 x 3 = 1125

total surface area = 1125 + 108 = 1233cm^2

7 0

2 years ago

In RST, R = 23* and S = 136*. Which list has the sides of RST in order from shortest to longest?

exis [7]

RS,ST,TR IS THE ANSWER

4 0

3 years ago

Read 2 more answers

Jennifer drives 265 miles in 5 hours what is her average rate of speed in miles per hour ?

algol [13]

Answer: 53

265 divided by 5=

53

hope this helps

7 0

3 years ago

Drag each real-world situation to the correct column to show whether it can be modeled by combining additive inverses to get 0.

Flauer [41]

Answer:

. An investment account earns 2.8% simple interest.

Since investment amount increases every year linearly, therefore, the modeled situation represents a LINEAR FUNCTION.

B). The price of a stock varies by 2.8% each week.

Since price of the stock may increase or decrease every week, therefore, this situation can't be modeled by any function.

Therefore, the answer is NEITHER.

C). An investment account earns 2.8% compound interest, compounded monthly.

Formula to get the value of the final amount in the account is,

Final value = Initial value ×

Here 't' = Duration of investment

It's an EXPONENTIAL FUNCTION.

Step-by-step explanation:

3 0

2 years ago

(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13

jolli1 [7]

Answer:

$y(x)=3e^{5x}-2xe^{5x}$

Step-by-step explanation:

The given differential equation is $y''-10y'+25y=0$

The characteristics equation is given by

$r^2-10r+25=0$

Finding the values of r

$r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5$

We got a repeated roots. Hence, the solution of the differential equation is given by

$y(x)=c_1e^{5x}+c_2xe^{5x}...(i)$

On differentiating, we get

$y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)$

Apply the initial condition y (0)= 3 in equation (i)

$3=c_1e^{0}+0\\\\c_1=3$

Now, apply the initial condition y' (0)= 13 in equation (ii)

$13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2$

Therefore, the solution of the differential equation is

$y(x)=3e^{5x}-2xe^{5x}$

5 0

3 years ago