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Oduvanchick [21]
3 years ago
11

The following triangle shows the length of each side using expressions.

Mathematics
1 answer:
grigory [225]3 years ago
4 0
Answer:

A). 2(2n+7)+3n

B). 2(2(8)+7)+3(8)
2(16+7)+ 24
2(23)+24
46+24
70
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Find the area and perimeter of each composite figure use 3.14 for pi round your answer to the nearest 10th
Ad libitum [116K]

1. Perimeter is 3 + 3 +3 +4 +5 = 18 feet

  Area = 3*3 = 9, 1/2*3*4 = 6, 9 + 6 =15 square feet

2. perimeter = 2.5 +2.5+ 2.5+2.5+0.5+0.5 = 11 meters

   Area = 3*.5 = 1.5, 3*2=6,  6+1.5 = 7.5 square meters

3. perimeter = 3.14*2*3 = 18.84 +8 = 26.8 inches

   Area = 6*4 = 24 + 3.14*3^2 = 28.26 = 28.26 +24 = 52.3 inches

4. surface area = 2*π*6*20+2*π*6^2= 980.2 yards

Volume = π*6^2*20 = 2261.9 cubic yards

5.surface area = 2*(9*7+2*2+2*9) = 190 cm

 Volume = 2*7*9 = 126 cubic cm

6. surface area = <span>2*(11*11+11*11+11*11) = 726 mm</span>

<span>  Volume = 11 *11*11 = 1331 cubic cm</span>


7 0
3 years ago
A diver went 25.65 feet below the surface of the ocean and then 16.5 feet further down he then rose 12.45 feet write and solve a
Anastaziya [24]
So a diver went 25.65 ft BELOW so it's negative.
then he went 16.5 ft further down, so that's negative also.
he then rose 12.45 ft, so that's positive.
so the expression is: -25.65+-16.5+12.45, the answer is 23.7
8 0
3 years ago
Find 2a for a = 3-<br> 4<br> = 34
Usimov [2.4K]

Answer:

68

Step-by-step explanation:

2a

2x34(adding value of a)

68

8 0
3 years ago
A package of 5 pairs of insulated socks costs $36.95. What is the unit price of the pairs of socks
Sergeeva-Olga [200]

Hey there! :)

Answer:

$7.39 per pair of socks.

Step-by-step explanation:

Find the price per pair of socks by dividing the total price by the number of socks:

36.95 ÷ 5 = $7.39 per pair of socks.

3 0
3 years ago
Read 2 more answers
99 POINT QUESTION, PLUS BRAINLIEST!!!
Basile [38]
1.Disc method.
In this method the volume is given by:

\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}

so:

V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}

A) Function f(x)=x^2 over the interval [1,3]
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.


2. Shell method.

In this case volume is given by:

</span></span>\boxed{V=2\pi\int\limits_a^bx\cdot f(x)\,dx}

So there will be:

V=\pi\int\limits_1^3x^4\,dx=\dfrac{2}{2}\cdot\pi\int\limits_1^3x^4\,dx=2\pi\int\limits_1^3\dfrac{x^4}{2}\,dx=&#10;\boxed{2\pi\int\limits_1^3x\cdot\dfrac{x^3}{2}\,dx}

A) Function f(x)=\dfrac{x^3}{2} over the interval [1,3]
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>
3 0
3 years ago
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