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aniked [119]
3 years ago
13

(√2)^3

qrt{2) {?}^{3 \\} " alt=" (\sqrt{2) {?}^{3 \\} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf

\sf 2 ^1\cdot \:2^{\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Refine}}\\\\\\\\\boxed{\sf =2\sqrt{2}}

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Just took the test. A is the right answer. 
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3 years ago
Read 2 more answers
F(x) = 12 + x<br> X<br> f(x)<br> -3<br> -1<br> 0<br> 4<br> 6
katen-ka-za [31]

9514 1404 393

Answer:

  (-3, 9), (-1, 11), (0, 12), (4, 16), (6, 18)

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