Answer: Option B is the cheaper deal (the 12 batteries for $14.76)
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Explanation:
For the first deal we can say
3 batteries = 4.80 dollars
3/3 batteries = 4.80/3 dollars .... divide both sides by 3
1 battery = 1.60 dollars
The unit price for the first deal is $1.60 per battery.
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For the second deal we could say
12 batteries = 14.76 dollars
12/12 batteries = 14.76/12 dollars .... divide both sides by 12
1 battery = 1.23 dollars
The unit price for the first deal is $1.23 per battery.
This is the cheaper deal.
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So in short, you're dividing the total cost over the number of items to get the unit price.
Answer:
CD||GH is "equal" ABD is "Right angle" and ABD||GEF is "Approximately equal"
Answer:
4-lower- 18
5-upper-29
6- range-56
Step-by-step explanation:
If you look up a completed box plot you can tell where lower and upper quartiles are. Range is found by Max-Min
Hope I helped...!
Answer:
- -3/13 ≈ -1/4
- -6/11 ≈ -1/2
- -7/9 ≈ -3/4
Step-by-step explanation:
We'll drop all the minus signs, since they don't contribute anything but distraction.
When numerators or denominators are relatively large, changing their value by 1 unit will have a relatively small effect on the value of the fraction. For example, ...
3/13 ≈ 3/12 = 1/4
If we compare the decimal values of these fractions, we see that ...
3/13 ≈ 0.230769... (6-digit repeating decimal)
The closest of the offered "reasonable estimate" fractions is 1/4 = 0.25.
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Likewise, 6/11 ≈ 6/12 = 1/2. In decimal, these fractions are ...
6/11 = 0.54... (2-digit repeat)
1/2 = 0.5
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We can also increase or decrease both numerator and denominator by the same amount to get a fraction with nearly the same value. This works best when the numbers are larger.
7/9 ≈ 6/8 = 3/4 . . . . . . both numerator and denominator decreased by 1
In decimal, these are ...
7/9 = 0.7... (1-digit repeat)
3/4 = 0.75
Answer:
The volume of the ball is or
Step-by-step explanation:
we know that
The volume of the sphere ( a ball) is equal to
we have
-----> the radius is half the diameter
substitute
----> exact value of the volume
assume
substitute
-----> approximate value