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3 years ago

PLZ HELP:

Mathematics

1 answer:

UkoKoshka [18]3 years ago

8 0

1. In each graph, the two lines are parallel to each other.

2. Each set of equations have the same slope.

3. Equations that have the same slope as each other will always be parallel to each other.

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URGENT DUE IN 20 MINUTES FOR GRADE PLEASE HELP<br> 2/3 (x-7)= -2

ASHA 777 [7]

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3 years ago

Find the measure of YVZ

Reptile [31]

Answer:

47 degrees

Step-by-step explanation:

Add all the numbers we know

the line is 180

43+52+38=133

133+47=180

47 Your answer. Hope this helped leave a heart or like or comment. :)

7 0

3 years ago

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Consider the quadratic function f(x) = –2x2 5x – 4. the leading coefficient of the function is?

evablogger [386]

Answer:

$\text{-2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

Step-by-step explanation:

Given the quadratic function

$f(x)=-2x^2+5x-4$

we have to find the leading coefficient of given quadratic equation.

$\text{The general form of quadratic equation is }ax^2+bx+c=0$

The coefficient of $x^2$ i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

$\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

3 0

3 years ago

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If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a

Luba_88 [7]

Answer:

$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

$nCx = \frac{n!}{x! (n-x)!}$

So then 12 C5 would be equal to:

$12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792$

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

$12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220$

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

$(12C5)*(12C3) = 792*220 =174240 ways$

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3 years ago

How can this expression be written another way?

aleksklad [387]

Answer:

(105 x 30) + (105 x 5) + m

Step-by-step explanation:

8 0

2 years ago

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