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yulyashka [42]
3 years ago
7

"Determine which three lengths cannot be the measure of the sides of a triangle. 2 m, 5 m, 6 m 8 m, 10 m, 17 m 5 m, 20 m, 22 m 4

m,15 m, 20 m"
Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

None.

All the four given measurements can form a triangle.

Step-by-step explanation:

Given;

first measurement, = 2m , 5m, 6m

second measurement, = 8m, 10m, 17m

third measurement, = 5m, 20m, 22m

fourth measurement, = 4m, 15m, 20m

For any of the three lengths to form a triangle, the sum of any two sides must be greater than the third side.

First measurement: 2m + 5m = 7m and 7m > 6m (can form a triangle)

Second measurement: 8m + 10m = 18m and 18m > 17m (can form a triangle)

Third measurement: 5m + 20m = 25m and 25m > 22m (can form a triangle)

Fourth measurement: 4m + 15m = 19m and 19m < 20m  BUT

                                  20 m + 15m = 35 m and 35 m > 4m (can form a triangle)

Therefore, all the four given measurements can form a triangle.

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Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

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Equate each factor to zero and solve for u

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Change u back into terms of x, that is

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3 years ago
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Answer:

Step-by-step explanation:

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You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

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I do not understand how I find answers on here
Volgvan
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