All categories

3 years ago

1) Find the measure of ∠θ. Round to one decimal place.

Mathematics

1 answer:

I am Lyosha [343]3 years ago

3 0

Answer/Step-by-step explanation:

Reference angle = θ

Opposite side = 11.9

Adjacent side = 10

Applying the trigonometric ratio, TOA, we have:

Tan θ = opp/adj

Tan θ = 11.9/10

θ = tan^{-1}(11.9/10)

θ = 49.9584509° ≈ 50.0° (to one d.p)

Apply pythagorean theorem to find AB:

Thus:

AB = √(11.9² + 10²)

AB = √241.61

AB ≈ 15.5 (to 1 d.p)

You might be interested in

What number adds up to be 12 but also multiplies to be 12

netineya [11]

4+3+1+1+1+1+1 =12
4x3x1x1x1x1x1=12

8 0

3 years ago

A rectangle has a width of 9 inches. The area of the rectangle is 648 square inches. What is the length, in inches, of the recta

Ivan

Answer:

The length is 72

Step-by-step explanation:

length x width = area

9 x length = 648

length = 72

7 0

3 years ago

Multiply (5 + 3i)(5 − 3i) 16 + 15i 16 − 15i 16 34

Annette [7]

Answer:

(5 + 3i)(5 − 3i) = 34

Step-by-step explanation:

The multiplication of two identical binomials who have different symbol, can be solved using the factoring case of a difference of squares:

$(a-b).(a+b)=a^{2}-b^{2}$

So, in this case:

$(5+3i).(5-3i) = 5^{2}-(3i)^{2}$

$=25-9i^{2}$

Remember that $i=\sqrt{-1}$

So: $i^{2}=-1$

We replace on the polynomial:

$=25-9.(-1) = 25+9=34$

3 0

3 years ago

Read 2 more answers

I need help with #4 a-d

lesya [120]

a repeating decimal is placed over 9's instead of 0's. for example: 0.23 = $\frac{23}{100}$ , but 0.232323... = $\frac{23}{99}$

a) x = 0.121212

b) 100(x) = 100(0.121212)

100x = 12.1212

c) 100x = 12.1212

- x = 0.1212

99x = 12

x = $\frac{12}{99}$

d) -2 $\frac{12}{99}$ = -2 $\frac{4}{33}$ when simplified

The number is rational becase it has a repeating decimal

6 0

3 years ago

Write the first 4 terms in the sequence defined by the explicit rule f(n)=n^2 - 5 *n^2 means n squared

Deffense [45]

The question did not spesify the stating value for n.

Assuming, n = 0 is the starting value.

1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5

2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4

3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1

4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4

Therefore, the first 4 terms are: -5, -4, -1, 4.

6 0

3 years ago