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Vinil7 [7]
3 years ago
10

Pls help, will give brainliest

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

area of 3rd figure is 20ft^2

and perimeter is 20 ft

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The candles turn out great! So, the candle maker raises her normal price and sells 5 candles for $ 27 . She usually charges $14.
weqwewe [10]
She raised the price by $0.65

14.25 divided by 3 =
$4.75 ( normal price per candle)

27 divided by 5 =
$5.40 (new price per candle)

$5.40 - $4.75 = $0.65
7 0
3 years ago
Which algebraic expression shows the average melting points of helium, hydrogen, and neon if h represents the melting point of h
LenKa [72]
Average = mean = sum of the values / number of data

Values = h, j, and k

Number of data = 3

Sum of the values = h + j + k

Mean = [h + j + k] / 3

=> Answer: option c. [h+j+k] over 3
4 0
3 years ago
Read 2 more answers
In the ordered (7,8) which number is the X COORDINATE?
PSYCHO15rus [73]

Answer:

7

Step-by-step explanation:

(x,y)

8 0
3 years ago
Read 2 more answers
Please help!! Due soon
Dafna1 [17]
Answer: 24 cm

-----------------------------------------------

Explanation:

Let
P = area of triangle ABC
Q = area of triangle ACD

The two areas mentioned above are in ratio 1.5:1 which basically means 
P = 1.5*k
Q = 1*k
for some value k
Notice how P/Q = (1.5k)/(1k) = 1.5 which proves that P:Q = 1.5:1

We can find the value of k by determining the area of triangle ABC
P = area of triangle ABC
P = (base)*(height)/2
P = 36*10/2
P = 360/2
P = 180

If P = 180, then
P = 1.5*k
1.5*k = 180
k = 180/1.5
k = 120

Telling us that
Q = 1*k
Q = 1*120
Q = 120
Q = area of triangle ACD
area of triangle ACD = 120 
note how P/Q = 180/120 = 1.5 so P:Q = 1.5:1

We'll use this area to find the base of triangle ACD which is AD

Area of Triangle ACD = (base)*(height)/2
120 = AD*10/2
120*2 = AD*10
240 = AD*10
240/10 = AD
24 = AD
AD = 24
5 0
3 years ago
In right ∆LMN, sin M = 0.759. What is cos N? A. 0.121 B. 0.241 C. 0.349 D. 0.651 E. 0.759
Hatshy [7]

Answer:

E. 0.759

Step-by-step explanation:

You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN

The sine of angle ∠LMN is 0.759, find the value of ∠LMN

sin^-1(0.759)=49.38

∠LMN=49.38°

Find angle ∠LNM

You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence

∠LNM=180°-(90°+49.38°)

∠LNM= 180°-139.38°=40.62°

Find cos 40.62°

Cos 40.62°=0.7590

6 0
4 years ago
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