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3 years ago

6

What is an equation of the line that passes through the points (3,4) and (5,8)

2 answers:

algol [13]3 years ago

6 0

Answer:

i think 5

Step-by-step explanation:

Delicious77 [7]3 years ago

6 0

Step-by-step explanation:

In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.

First, you should find the slope of the line. To do this, use the equation M=y2-y1/x2-x1. Using the two given points (3,6) and (8,4), you can solve for M.

M=4-6/8-3

M=-2/5 (-0.4 in decimal form)

Now, your equation is y=-0.4x+b

Next you must solve for b to find the y-intercept. You can do this by subbing one of the given points in for x and y.

Using the point (3,6):

y=-0.4x+b

6=-0.4(3)+b

6=-1.2+b

Isolate b:

6+1.2=b

b=7.2

And now you have the equation of the line!

y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)

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A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling

lara31 [8.8K]

Answer:

a) weight of the car = 2816,1 lbs

b) 2773 lbs

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The external force 490 lbs

weight of the car uknown

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3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

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Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

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$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

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Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

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Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

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Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

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