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prisoha [69]
3 years ago
14

Network id is 192.168.10.32/28. what would be the ip address, if you assign the last available ip address in the range

Computers and Technology
2 answers:
Yakvenalex [24]3 years ago
6 0
192.168.10.47 would be the multicast address for this network.
Yuliya22 [10]3 years ago
3 0

IP address:

192.168.10.47 would be the multicast address for this network

Further Explanation:

When you receive a block of addresses from an ISP, what you get will look something like this: 192.168.10.32/28. This is telling you what your subnet mask is. The slash notation (/) means how many bits are turned on (1s). Obviously, the maximum could only be /32 because a byte is 8 bits and there are 4 bytes in an IP address: 4 × 8 = 32. But keep in mind that the largest subnet mask available (regardless of the class of address) can only be a /30 because you have to keep at least 2 bits for host bits.

192.168.10.47:

IP address 192.168.10.47 is registered by the Internet Assigned Numbers Authority (IANA) as a part of private network 192.168.10.0/24. ... The fixed IP address of such a device in network range 192.168.10.0/24 would generally be 192.168.10.1 or 192.168.10.254 depending on the provider.

An example of a NAT gateway would be a wired or wireless router you receive from a broadband provider. The fixed IP address of such a device in network range 192.168.10.0/24 would generally be 192.168.10.1 or 192.168.10.254 depending on the provider. A gateway web interface should be available through the HTTP (Hypertext Transfer Protocol) and/or HTTPS (Hypertext Transfer Protocol Secure) protocols. To try this you should enter 'http://ip address' or 'https://ip address' in the address bar of your favorite web browser like Google Chrome or Mozilla Firefox and log in with the username and password provided by your provider.

You can use these types of (private network) IP addresses in your local network and assign it to your devices such as a personal computer, laptop, tablet and/or smartphone. It is also possible to configure a range within a DHCP (Dynamic Host Configuration Protocol) server to do the IP assigning automatically.

Learn more:

  • How many host ids does a /20 network support?

brainly.com/question/7758629

Keywords: IP address, network, host, classes of network, gateway, subnet mask, HTTP, HTTPS, NAT, DHCP.

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2 years ago
Discuss the software development methodology you would use for developing a software product for insurance agents, and state val
nadya68 [22]

Answer:

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Explanation:

4 0
3 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
Create an Automobile class for a dealership. Include fields for an ID number, make, model, color, year, vin number, miles per ga
aliya0001 [1]

Answer:

public class TestAutomobiles {

   public static void main(String args[]) {

     Automobile obj = new Automobile(1, "Wolkswagen", "Golf", 2007, "GR1GR", 20, 120, "Grey");

  System.out.println("Initial Speed: " + obj.getSpeed());

  System.out.println("Current Speed with acceleration 100: " + obj.accelerate(100));

  System.out.println("Current Speed after using brake : " + obj.brake());

   }

}

class Automobile {

    private int idNumber, year, milesPerGallon, speed = 0;

    private String model, vinNumber, make, color;

   

    public void setIdNumber(int idNumber){

       if (idNumber >= 0 && idNumber <= 9999)

           this.idNumber = idNumber;

       else this.idNumber = 0;

    }

    public void setModel(String model){

        this.model = model;

    }

    public void setYear(int year){

       if (year >= 2000 && year <= 2017)

           this.idNumber = idNumber;

       else this.year = 0;

    }

    public void setVinNumber(String vinNumber){

        this.vinNumber = vinNumber;

    }

    public void setMilesPerGalon(int milesPerGallon){

       if (milesPerGallon >= 10 && year <= 60)

           this.milesPerGallon = milesPerGallon;

       else this.milesPerGallon = 0;

    }

    public void setSpeed(int speed){

        this.speed = speed;

    }

    public void setMake(String make){

        this.make = make;

    }

    public void setColor(String color){

        this.color = color;

    }

    public int getIdNumber(){return idNumber;}

    public String getModel(){return model;}

    public int getYear(){return year;}

    public String getVinNumber(){return vinNumber;}

    public int getMilesPerGallon(){return milesPerGallon;}

    public int getSpeed(){return speed;}

    public String getMake(){return make;}

    public String getColor(){return color;}

   

   public int accelerate() {

       setSpeed(speed + 5);

       return speed;

   }

   public int brake() {

       setSpeed(speed - 5);

       return speed;

   }

   public int accelerate(int s) {

       setSpeed(speed + s);

       return speed;

   }

   public int brake(int s) {

       setSpeed(speed - s);

       return speed;

   }

   

    public Automobile(int idNumber, String make, String model, int year, String vinNumber, int milesPerGallon, int speed, String color){

       setIdNumber(idNumber);

       setModel(model);

       setYear(year);

       setVinNumber(vinNumber);

       setMilesPerGalon(milesPerGallon);

       setSpeed(speed);

       setMake(make);

       setColor(color);

    }

}

Explanation:

Required <em>variables</em> are declared as private members.

Their <em>setters</em> and <em>getter</em> are created.

Two <em>accelearate</em> and two <em>break</em> methods are created.

One <em>constructor</em> taking all variables as parameter is created.

In the main, I tested a few functions to check if they work properly.

4 0
3 years ago
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