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Harrizon [31]
2 years ago
10

*

Mathematics
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

Option 2 and 5 are correct. Look down for my explanation↓:

Step-by-step explanation:

So We need to tell which one of them is quadratic function.

Option 1 is exponential decay so, it is not quadratic.

Option 2 is quadratic because the diver will take the parabolic shape when jumps.

Option 3 is not quadratic. Option 4 is not quadratic it is linear.

Option 4 is again exponential not quadratic.

Option 5 is quadratic because it takes the parabolic shape again.

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PLZ HELP!!!
Fed [463]
4 is missing I assume. But I could be wrong
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2 years ago
If f(x) = ||x|| , find f(−14)
bogdanovich [222]

Answer:

14

Step-by-step explanation:

f(-14) = ||-14|| = |14| = 14

3 0
3 years ago
Read 2 more answers
A town has a population of 13,000 and grows at 5% every year what will the population be after 11 years to the nearest whole num
scoray [572]
This question is based on the concept of
amount of interest. Therefore, 22,234 would be
the population after 11 years, to the nearest
whole number.
Given:
A town has a population of 13000 and grows at
5% every year.
We need to determined the population after 11
years, to the nearest whole number.
We know that,
Formula =A = P(1+ r)
Where, p be the population. r is the rate and t is
the time.
P= 13000,
r= 5%
†= 11
Now put all these values in formula.
We get,
5
A = 13000(1 +
A
= 13000(1 + 0.05)11
A
= 1300022, 234.41(0.95)
5 0
2 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
Describe the transformation f(x)=-2x-4;r(x)=(1/2x)
Evgesh-ka [11]
F(x) is a Virtical stretch that is reflected over the y axis moved 4 to the right

R(x) is a Horrizontal shrink


4 0
3 years ago
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