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hodyreva [135]
3 years ago
9

I literally am so cofused

Mathematics
2 answers:
musickatia [10]3 years ago
6 0
The ratio on the lines state: gallons to cups is 4:64
This means for every 4 gallons, there are 64 cups. If you divide 64 by 4 you get 16.
Now you know for every 1 gallon, there are 16 cups.
Multiply 16 by 3 so you can figure out how many cups there will be for every 3 gallons.
The answer is 48 cups. For every 3 gallons, there will be 48 cups.
ANTONII [103]3 years ago
5 0

Answer:

48 cups

Step-by-step explanation:

There are 16 cups in 1 gallon. I know this because i divided 64 by 4 to get the amount added. If you subtract 16 from 64, you get 48 cups.

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5x+18/8 = x/4 <br> Solve for x
ollegr [7]

Answer: x= -9/19

Step-by-step explanation:

5x+18/8=x/4

5x+ 9/4=x/4

5x+9/4-9/4=x/4-9/4

5x= x-9/4

5x(4)=x-9/4(4)

20x=x-9

20x-x=x-9-x

19x=-9

19x/19=-9/19

x=-9/19

8 0
3 years ago
Find an explicit solution of the given initial-value problem.dy/dx = ye^x^2, y(3) = 1.
tamaranim1 [39]

Answer:

y=exp(\int\limits^x_4 {e^{-t^{2} } } \, dt)

Step-by-step explanation:

This is a separable equation with an initial value i.e. y(3)=1.

Take y from right hand side and divide to left hand side ;Take dx from left hand side and multiply to right hand side:

\frac{dy}{y} =e^{-x^{2} }dx

Take t as a dummy variable, integrate both sides with respect to "t" and substituting x=t (e.g. dx=dt):

\int\limits^x_3 {\frac{1}{y} } \, \frac{dy}{dt} dt=\int\limits^x_3 {e^{-t^{2} } } dt

Integrate on both sides:

ln(y(t))\left \{ {{t=x} \atop {t=3}} \right. =\int\limits^x_3 {e^{-t^{2} } } \, dt

Use initial condition i.e. y(3) = 1:

ln(y(x))-(ln1)=\int\limits^x_3 {e^{-t^{2} } } \, dt\\ln(y(x))=\int\limits^x_3 {e^{-t^{2} } } \, dt\\

Taking exponents on both sides to remove "ln":

y=exp (\int\limits^x_3 {e^{-t^{2} } } \, dt)

7 0
3 years ago
What is the remainder when 1000 to the power of 1000 is divided by 6?
Liono4ka [1.6K]

Answer:

166.666.667

Hopes this helps

Step-by-step explanation:

8 0
3 years ago
Rudy has been paying an annual homeowners insurance premium of $1,106.30 ($0.37 per $100 of value) since he first purchased his
iren [92.7K]

If Rudy successfully adds $50,000 to the value of his house, his new annual homeowner's insurance premium be <u>c. $1,291.30</u>.

<h3>What is the annual homeowner's insurance premium?</h3>

The annual homeowner's insurance premium is the insurance charge that the homeowner pays as an insurance premium annually.

The insurance premium is calculated using some set formulas determined by these factors:

  • Home's value
  • Location
  • Coverage Value
  • Safety features
  • Deductibles.

<h3>Data and Calculations:</h3>

Insurance premium rate = $0.37 per $100

Current insurance premium = $1,106.30

Added value to the house = $50,000

Added premium = $185 ($50,000 x $0.37/$100)

New insurance premium = $1,291.30 ($1,106.30 + $185)

Thus, if Rudy successfully adds $50,000 to the value of his house, his new annual homeowner's insurance premium be <u>c. $1,291.30</u>.

Learn more about the annual homeowner's insurance premium at brainly.com/question/26133348

#SPJ4

8 0
2 years ago
What are some Solutions to the linear equation?: 3x+y=-8
svetlana [45]

9514 1404 393

Answer:

  (0, -8), (1, -11), (-1, -5)

Step-by-step explanation:

It is convenient to solve for y and choose values of x.

  y = -3x -8 . . . . . subtract 3x from both sides of the equation

Now, any integer value of x you choose will result in an integer value of y. Often, it is convenient to choose values near zero.

  x = -1, y = -3(-1) -8 = 3 -8 = -5 . . . . solution: (-1, -5)

  x = 0, y = -3(0) -8 = -8 . . . . solution: (0, -8)

  x = 1, y = -3(1) -8 = -11 . . . . solution: (1, -11)

7 0
3 years ago
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