Answer:
17.32m ; 110°
Step-by-step explanation:
Distance between X and Z
To calculate the distance between X and Z
y^2 = x^2 + z^2 - (2xz)*cosY
x = 20, Z = 10
y^2 = 20^2 + 10^2 - (2*20*10)* cos60°
y^2 = 400 + 100 - (400)* 0.5
y^2 = 500 - 200
y^2 = 300
y = sqrt(300)
y = 17.32m
Bearing of Z from X:
Using cosine rule :
Cos X = (y^2 + z^2 - x^2) / 2yz
Cos X = (300 + 100 - 400) / (2 * 20 '*10)
Cos X = 0 / 400
Cos X = 0
X = cos^-1 (0)
X = 90°
Bearing of Z from X
= 20° + X
= 20° + 90°
= 110°

Use long division for dividing
Here 'v' term is missing so we use 0vW
Divide
by v-10 using long division
Step 1: Put 8v^2 at the top
step 2: multiply 8v^2 with v-10 and put it at the bottom
step 3: subtract it
We will get remainder 6
so quotient is 
Remainder is 6
-2(4g-3)= 30
-8g+6= 30
-8g=30-6
-8g= 24
G= 24/-8
G= -3
Hope this helps!
Answer:
I guess they subtracted a 110 from -110 instead of subtracting from 360
5x -3 = 12
5x -3 + 3 = 12 + 3 [Add 3 to each side]
5x + 0 = 15 [Evaluate]
5x/5 = 15/5 [Divide each side by 5]
1x = 3 [Evaluate]
The answer I get is the number 3.