Question

Help ASAP please!!!!!!!!!​​

Answer 1

Answer:

Δ JKL is similar to Δ ABC ⇒ D

Step-by-step explanation:

Similar triangles have equal angles in measures

In ΔABC

∵ m∠A = 15°

∵ m∠B = 120

∵ The sum of the measures of the interior angles of a Δ is 180°

∴ m∠A + m∠B + m∠C = 180°

→ Substitute the measures of ∠A and ∠B

∵ 15 + 120 + m∠C = 180

→ Add the like terms in the left side

∴ 135 + m∠C = 180

→ Subtract 135 from both sides

∴ 135 - 135 + m∠C = 180 - 135

∴ m∠C = 45°

The similar Δ to ΔABC must have the same measures of angles

If triangles ABC and JKL are similar, then

m∠A must equal m∠J

m∠B must equal m∠K

m∠C must equal m∠L

∵ m∠J = 15°

∴ m∠A = m∠J

∵ m∠L = 45°

∴ m∠C = m∠L

∵ m∠J + m∠K + m∠L = 180°

→ Substitute the measures of ∠J and ∠L

∵ 15 + m∠K + 45 = 180

→ Add the like terms in the left side

∴ 60 + m∠K = 180

→ Subtract 60 from both sides

∴ 60 - 60 + m∠K = 180 - 60

∴ m∠K = 120°

∴ m∠B = m∠K

∴ Δ JKL is similar to Δ ABC