Metallic silver has a density of 10.50. what is the mass, in g, of a silver ingot that is 28.0 cm long, 4.90 cm wide, and 3.60 c
m thick?
1 answer:
Answer:
5190 g
Step-by-step explanation:
Calculate the volume:
28.0 cm × 4.90 cm × 3.60 cm = 493.92 cm³
Density is mass divided by volume:
D = M / V
Solving for mass:
M = D V
Substituting values:
M = (10.50 g/cm³) (493.92 cm³)
M = 5186.16 g
Rounding to three significant figures, the mass is 5190 g.
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