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3 years ago

Super hard question :0 what is 3+3

1 answer:

5 0

Well sir according to my calculations if you have a 3 and than you add 3 to the 3 you already have then you would end up with the exact answer of number 6

You might be interested in

Select all the equations that have the same solution as the equation 3x – 12 = 24

Stolb23 [73]

Your answer will be D and E

7 0

3 years ago

Find the midpoint of the segment with the given endpoints.<br> (-10,- 6) and (-3,7)

Marina CMI [18]

Step-by-step explanation:

in essence, these 2 points are the Hypotenuse of a right-angled triangle. the legs are the coordinate differences between the 2 points creating the 3rd point of that triangle at (-10, 7) : the x coordinate of one point, and the y coordinate of the other.

now, we are looking for the midpoint. this midpoint cuts the original line/hypotenuse in half creating a scaling factor of 1/2.

when we create now a similar triangle based on that "half- Hypotenuse", we need to use the same scaling factor also on the legs (the coordinate differences).

so, when we cut the coordinate differences also in half, we get the coordinates for the midpoint on the main line.

xm, ym are the coordinates of the midpoint.

xm = (x1 + x2)/2 = (-10-3)/2 = -13/2 = -6.5

ym = (y1 + y2)/2 = (-6+7)/2 = 1/2 = 0.5

so, the midpoint is (-6.5, 0.5)

8 0

2 years ago

Consider the first order differential equation

AURORKA [14]

Answer:

For y(-7) =6.4

The largest interval is between

$-\infty \to -5$

For y(-2.5) = -0.5.

The largest interval is between

$-5 \to 5$

For y(0) = 0

The largest interval is between

$-5 \to 5$

For y(4.5) = -2.1.

The largest interval is between

$-5 \to 5$

For y(14)= 1.7.

The largest interval is between

$9 \to \infty$

Step-by-step explanation:

From m the question we are told that

The first order differential equation is $\frac{y' - t}{ t^2 -25} = \frac{e^t}{t-9}$

Now the first step is to obtain the domain of the differential equation

Now to do that let consider the denominators

Now generally

$t^2 - 25 \ne 0$ side calculation

=> $t\ne \pm5$ $t^2 - 25 = 0$

$t = \pm 5$

Also $t-9\ne 0$ $t -9 = 0$

=> $t\ne 9$ $t= 9$

This means that this first order differential equation is discontinuous at

$t = -5 , \ \ t = 5 \ \ t = 9$

$This \ is \ illustrated \ below \ \\ ------------------\\\. \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ |\\. \ -5 \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ 9$

For y(-7) =6.4

The largest interval is between

$-\infty \to -5$

For y(-2.5) = -0.5.

The largest interval is between

$-5 \to 5$

For y(0) = 0

The largest interval is between

$-5 \to 5$

For y(4.5) = -2.1.

The largest interval is between

$-5 \to 5$

For y(14)= 1.7.

The largest interval is between

$9 \to \infty$

4 0

3 years ago

A mountain climber started at zero elevation. The first day he hiked 10 miles up

Mandarinka [93]

Answer:

14 miles if that's how far he went up

17miles if you're calculating his distance covered

4 0

2 years ago

What is the least common denominator for 1/9 and 5/2

schepotkina [342]

Answer: 18

Step-by-step explanation:

1/9 = 2/18

5/2 = 45/18

6 0

2 years ago