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Len [333]
3 years ago
10

What is the end behavior in the function y=2x^3-x

Mathematics
1 answer:
sasho [114]3 years ago
6 0

Answer:

Step-by-step explanation:

When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.

Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.

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Answer with explanation please! tysvm!
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Step-by-step explanation:

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Mary can either take her lunch or buy it at school. It cost 1.95 to buy lunch. If she wants to spend no more than $30 on lunch p
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Step-by-step explanation:

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3 0
3 years ago
When Anthony was born, his mom put aside $1000 in a savings account that earns 1% interest compounded monthly. When Anthony is 1
Elanso [62]
The applicable formula is;

A = P(1+r)^nt

Where
A = Accumulate amount
P = Initial invested amount
r = Annual interest rate
n = Number of  payments in a year
t = Time in years

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8 0
3 years ago
Please help me im confused . . . ? ? ? ?
saw5 [17]

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3 years ago
Which of the following points are not solutions of 2y-5x>6?
fgiga [73]
Answer is <span>C. II and IV not solutions
</span>

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(5,-5/3)....2y-5x = 2(-5/3) - 5(5) = -10/3  -25 = - 28 1/3  >  6 False

(3/4,5)....2y-5x = 2(5) - 5(3/4) = 10  -15/4 = 10 - 3.75 = 6.25  >  6 True

(2.6,5)....2y-5x = 2(5) - 5(2.6) = 10  - 13 = -3  >  6 False
8 0
3 years ago
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