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3 years ago

Find the missing side of the angle. Need help,==== thank you!!

Mathematics

1 answer:

Pavel [41]3 years ago

5 0

Answer: square root(265)

Step-by-step explanation:

Again, you can solve this via the Pythagorean theorem(a^2+b^2=c^2)

a= a side

b= another side

c= hypotenuse

Now, Substitute

12^2+11^2=x^2

144+121= 265

Now, square root and you get

square root(265)

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m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21

AnnZ [28]

The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!

6 0

3 years ago

HELPP YALL! I WILL MARK BRAINIEST!! LOOK AT THE PICTURE!!

kow [346]

then

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3 years ago

Read 2 more answers

5(2y-3)-4y=8-2y-15

dezoksy [38]

The answer is Y=1
5(2y-3)-3y=8-2y-15
10y-15-4y=8-2y-15
4y= 4y
———————————-
10y-15= 8+2y-15
15= 15
———————————
10y= 8+2y
-2y= -2y
———————————-
8y=8
—— —-
8 8
Y=1

5 0

3 years ago

Which is an equation of the line that has a slope of 1/2 and passes through the point (2, 4)?

irina1246 [14]

Answer: $y = \frac{1}{2}x +3$ (Choice A)

Work Shown:

$y - y_1 = m(x - x_1)\\\\y - 4 = \frac{1}{2}(x - 2)\\\\y - 4 = \frac{1}{2}x + \frac{1}{2}(- 2)\\\\y - 4 = \frac{1}{2}x - 1\\\\y = \frac{1}{2}x - 1+4\\\\y = \frac{1}{2}x +3\\\\$

Explanation: I started with the point-slope form. Then I plugged in the given slope m = 1/2 and the point (x1,y1) = (2,4). Afterward I solved for y.

The answer is in slope-intercept form y = mx+b

3 0

1 year ago

Solve each equation l x+11 l=8 l 3x-2 l=16

kobusy [5.1K]

|x + 11| = 8
x + 11 = 8
 -11 -11
 x = -3

|3x - 2| = 16
3x + 2 = 16
 -2 -2
 3x = 14
 3 3
 x = 4 2/3

3 0

3 years ago