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GaryK [48]
3 years ago
9

If a baseball player get a hit in 31% of his at-bats, what is the probability that he will

Mathematics
1 answer:
solong [7]3 years ago
3 0

Given:

A baseball player get a hit in 31% of his at-bats.

To find:

The probability that he will  get a hit 5 at-bats in a row.

Solution:

Since, a baseball player get a hit in 31% of his at-bats, therefore

Probability that he get a hit = \dfrac{31}{100}

                                           = 0.31

Now, the probability that he will  get a hit 5 at-bats in a row is

P=0.31\times 0.31\times 0.31\times 0.31\times 0.31

P=(0.31)^5

P=0.0028629151


Therefore, the required probability is (0.31)^5 and it can be written as 0.0028629151 .

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Answer:50/500×100=10%

Therefore, 10% of 500 is 50.

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Step-by-step explanation:

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y=(1/3)x-2

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Do the following exercise.
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A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

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3 years ago
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