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Fittoniya [83]
3 years ago
10

Find the slope of the line that passes through each pair of points. C(0, –2), D(3, -2)

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

0

Step-by-step explanation:

y2-y1/x2-x1

-2+2/3-0

0/3

= 0

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How to write 4(4*10^5) in scientific notation
Ne4ueva [31]

Answer:

16,000,000

Step-by-step explanation:

to start off your going to need to use PEMDAS (parenthesis exponents multiplication division addition subtraction)

so we are going to start IN the parenthesis  the next step is doing the exponents so its going to look like this 1,000,000

rewrite the problem: 4(4×1,000,000)

use the next step in PEMDAS multiplication rewrite the problem:

4(4,000,000)

multiply: 16,000,000

3 0
3 years ago
You are measuring the height of a statue. You stand 17 feet from the base of the statue. You measure the angle of elevation from
olga_2 [115]

Answer:

height ≈ 31 ft

Step-by-step explanation:

The illustration below will form a right angle triangle. He is standing 17 ft away from the base of the statue.  The angle of elevation from the ground to the top of the statue  is 61°. The height of the statue can be computed below.

adjacent side of the triangle = 17 ft

opposite side = a

Using SOHCAHTOA principle

tan 61° = opposite/adjacent

tan 61° = a/17

cross multiply

a = 17 tan 61°

a = 17 × 1.80404775527

a = 30.6688118396

a ≈ 31 ft

6 0
3 years ago
using the formula v=l×w×h , find the volume of a right rectangular prism when the length of the prism is 45cm , the width is 12c
Natali [406]
The volume of the rectangular of prism is 5400
3 0
3 years ago
Read 2 more answers
Simplify<br><br>-5/7(-(1 1/3-3/4)+1/3 / 4
koban [17]

Answer:

=5/21L+ -5/84

Step-by-step explanation:

=-(5/7) (-(1L/3-3/4)+1/3/4)

=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)

=5/21L= -15/28+ -5/84

=5/21L=+ -25/42

7 0
3 years ago
Solve and explain your reasoning (x+3)=-6​
densk [106]

Answer:

(x+3)=-6

x=-6-3

x=-9

Step-by-step explanation:

Hope it helps!

When side changes positive changes into negative.

5 0
3 years ago
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