An organic compound, Z, will react with calcium metal to produce a salt with the empirical formula
2 answers:
Answer:
The compound Z must be ethanoic acid.
Explanation:
It is clear from the options that the reaction is of an acid with calcium metal. The first acid given is monoprotic so one mole of calcium will react with two moles of acid to give calcium salt of diacid.
As per the given formula of the salt produced there are four carbons in the compound with one calcium so there must be two carbons in the acid with which calcium was reacted Or if the acid reacted is diprotic acid then there must be four carbon in it.
The molecular formulae of given acids are:
a) ethanoic acid: CH₃COOH [two carbons and it will form Ca(CH₃COO)2 or CaC₄H₆O₄.
b) butanedioic acid: C₄H₆O₄
If it will react with calcium it will form CaC₄H₄O₄: so it cannot be the compound "Z".
c) methylpropanedioic acid: C₄H₆O₄
If it will react with calcium it will form CaC₄H₄O₄: so it cannot be the compound "Z".
The structure are also shown in the figure.
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Answer: 0.0345 sec
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
k= rate constant =
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
for completion of 20 % of reaction
The time taken for the concentration of to decrease to 20% to its natural value is 0.0345 sec