We will have to use the formula for the area of a trapezoid on this problem, which is ( $b_1$ and $b_2$ are the bases of the trapezoid and $h$ is the height):

$\dfrac{b_1 + b_2}{2} \cdot h$

All we need to do is substitute the information we are given into our formula:

$\dfrac{21 + b_2}{2} \cdot 4 = 68$

Now, let's just simplify the equation:

$\dfrac{21 + b_2}{2} \cdot 4 = 68$

$\dfrac{21 + b_2}{2} = 17$

$21 + b_2 = 34$

$b_2 = 13$

The missing base has a length of 13 units.

4 0

3 years ago

How do I solve this?

Crazy boy [7]

Answer:

71°

142°

Step-by-step explanation:

$\because QS \: is \: the \: bisector \: of \: \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\ \because \: m\angle \: PQR = m\angle PQS + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree + 71\degree \\ \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}$

7 0

3 years ago

How many fluid ounces are in 3 quarts and 2 cups ?

sasho [114]

15 fluid ounces.
1quart= 4 cups

8 0

3 years ago

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