Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
Answer:
x = 5, -1
Step-by-step explanation:
0 = 3x^2 - 12x - 15 or
3x^2 - 12x - 15 = 0
By solving for x, use the Quadratic Formula.
… x = 5 and/or -1
So the equation is A = P(1+rt)
A = 10,000(1+0.07*6)
A = 10,000(1+0.42)
A = 14,200.00
Area=LW
<span>10x^2-29x-21=area
factor and those are the lengh and width
(2x-7)(5x+3)
perimiter=2(L+W)
P=2(2x-7+5x+3)
P=2(7x-4)
P=14x-8
answer is D
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