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3 years ago

This property says you can rewrite 3x(4+5) as (3x4) + (3x5)

Mathematics

1 answer:

daser333 [38]3 years ago

6 0

Distributive property
Step-by-step explanation:
Distributive property says that x(y + z) = (x*y) + (x *z)

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I have four times as much money as my brother has. Our total is $55. How much does each of us have?

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Answer:

27.5

Step-by-step explanation:

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The order pairs (1, 2), (2, 5), (3, 10), (4, 17), and (5, 26) represent a function. What is a rule that could represent this fun

Sever21 [200]

Answer:

The answer is A

Step-by-step explanation:

1 to the second power is 1 + 1 = 2

2 to the second power is 4 + 1 = 5

3 to the second power is 9 + 1 = 10

4 to the second power is 16 + 1 = 17

5 to the second power is 25 + 1 = 26

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3 years ago

How do I do this? <br><br> -2(6-r)=4

Tcecarenko [31]

Answer:r=8

Step-by-step explanation:

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3 years ago

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(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

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3 years ago