All categories

3 years ago

In thefigurebelow determine the densityLiquid X20cmLiquid x

Physics

1 answer:

krek1111 [17]3 years ago

5 0

Answer:

The molecules of different liquids have different size and mass. The mass and size of the molecules in a liquid and how closely they are packed together determine the density of the liquid. Just like a solid, the density of a liquid equals the mass of the liquid divided by its volume; D = m/v. The density of water is 1 gram per cubic centimeter.

Explanation:

You might be interested in

An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. Calculate the centripetal acce

tekilochka [14]

Given:

Object in circular motion 25 m/s

1 second to go quarter circle

Required:

Centripetal acceleration:

Solution:

Acceleration = v2/r

Where v is the velocity and r is the radian

Substituting the values into the equation,

Acceleration = v2/r = (25 m/s)2/(4*pi/180) = 8952.47 m2/s2

4 0

4 years ago

A boy of mass 50 kg exerts a pressure of 25000 pa calculate the area

gtnhenbr [62]

Answer: A = 0.02 m²

Explanation: Solution:

Pressure is expressed in the formula:

P = F / A where F = mg

= mg /A

= 50 kg ( 9.8 m/s²) / 25000 Pa

= 0.02 m²

3 0

3 years ago

A 20 kg block rests on a rough horizontal table. A rope is attatched to the block and is pulled with a force of 80 N to the left

Pani-rosa [81]

Given :

Mass of block , M = 20 kg .

Force applied , F = 80 N .

Acceleration of block , $a=2.5\ m/s^2$ .

To Find :

The coefficient is Kinetic force friction between the block and the table .

Solution :

We know , Force equation on block is given by :

$F_{net }=F-\mu_k mg \\\\ma = F-\mu_k mg \\\\20\times 2.5 = 80 -\mu_k \times 20 \times 10\\\\\mu_k\times 200=30\\\\\mu_k=\dfrac{30}{200}\\\\\ mu_k=0.15$

Therefore , coefficient is Kinetic force friction between the block and the table is 0.15 .

Hence , this is the required solution .

5 0

4 years ago

A _____ resource could run out thousands of years from now.

tresset_1 [31]

The answer is B. Nonrenewable

5 0

3 years ago

To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th

il63 [147K]

The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

m of water displaced = 65.5 kg

Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

The mass of athlete can also be calculated using, F = m*g

m of athlete = 690 N/ 9.8m/s^2

m of athlete = 70.41 kg

Knowing the volume and mass of athlete, her average density is therefore:

average density = 70.41 kg / 65.5 L

<span>average density = 1.07 kg/L = 1.07 g/mL</span>

5 0

3 years ago

Read 2 more answers

In thefigurebelow determine the densityLiquid X20cmLiquid x​

In thefigurebelow determine the densityLiquid X20cmLiquid x