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lyudmila [28]
4 years ago
10

A balsa wood raft is 1.50 m long, 1.00 m wide, and 0.120 m high. the density of balsa is 380 kg/m^3. what is the mass of the raf

t?(unit=kg)
Physics
1 answer:
topjm [15]4 years ago
4 0

Answer:

the mass of the raft is 68.4 kg

Explanation:

Since Mass is defined as Volume times Density, start by calculating the volume of the raft:

Volume = length x width x high = 1.5 m x 1.0 m x 0.12 m = 0.18 m^3

and now multiply it times the given density in order to find its mass:

Mass = Volume x Density = 0.18 m^3 x 380 kg/m^3 = 68.4 kg.

Notice that the m^3 units cancel out (they are in numerator and in denominator) leaving just the kg (a unit of mass) in the answer.

Therefore, the mass of the raft is 68.4 kg

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A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns
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Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

f'=\frac{V+V_{o}}{V-V_{s}} f  (1)

Where:

f=250,000 Hz is the actual frequency of the sound wave

f'=240,000 Hz is the "observed" frequency

V=340 m/s is the velocity of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which is the balloon

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}  (2)

V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}  (3)

V_{s}=-14.16 m/s (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (t=4.8 s) given as data, we can find the distance:

d=V_{s}t (5)

d=(14.16 m/s)(4.8 s) (6)

Finally:

d=68 m (8) This is the distance of the balloon from the radar station

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A rope is pulling a sled is sloped at 25 degrees upward at the point of contact. The tension in the rope is 40.0N. What is the h
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horizontal component of the force = force * cos(25°)

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horizontal component of the force = 40.0 N * cos (25°) = 36.25 N

Answer: 36.25 N
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