What happens when gasoline is used to power a vehicle?
1 answer:
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Answer:
<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>
Explanation:
<u>Free Fall Motion </u>
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:
y = 2.54 m
The final speed is computed below:
vf = 7.06 m/s
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s
Answer:
option d is correct
work done is 647 J
Explanation:
Given data
pressure P = 3 atm
volume V1 = 2 L
volume V2 = 8 L
to find out
work is done by the gas
solution
we know that work done formula that is
work done = k ( -
) / n
here n = 1 - γ
and k = PV^γ
and we know for diatomic gas γ = 1.4
so k will be = ( 3× 101325 ) ×
k = 50.62
so that now
work done = k ( -
) / n
work done = 50.62 ( -
) / 1-1.4
so work done will be 647 J
so option d is correct
work done is 647 J