Angle 1 and angle 2 form a linear pair. If the measure of angle 1 = (5x+9)º and
1 answer:
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We know that
if two lines are perpendicular
then
m1*m2=-1
where
m1 and m2 are the slopes of the lines
step 1
For <span>Y=(1/2)X-1
</span>slope m1=(1/2)
so
m2=-1/m1-----------> m2=-1/(1/2)-------> m2=-2
step 2
with m=-2 and the point <span>(2,5) find the equation of the line
y-y1=m*(x-x1)------> y-5=-2*(x-2)-----> y=-2x+4+5------> y=-2x+9
the answer is
y=-2x+9
see the attached figure</span>
if two lines are perpendicular
then
m1*m2=-1
where
m1 and m2 are the slopes of the lines
step 1
For <span>Y=(1/2)X-1
</span>slope m1=(1/2)
so
m2=-1/m1-----------> m2=-1/(1/2)-------> m2=-2
step 2
with m=-2 and the point <span>(2,5) find the equation of the line
y-y1=m*(x-x1)------> y-5=-2*(x-2)-----> y=-2x+4+5------> y=-2x+9
the answer is
y=-2x+9
see the attached figure</span>
Answer:
12. h=3
13. h=-3
Step-by-step explanation:
12. Recall that is a horizontal shift since h is being applied within the operation to the input. This means that h will slide the function left or right. Since the function f has a point at (1,-2) and g has the same point at (4,-2) then the function has moved 3 units 1+3=4 to the right. h=3.
13. Once again, h is a horizontal shift meaning the graphs has moved left or right only. Looking at g it has a point at (-2,2) while f has the same point at (1,2). So the graph f has moved to the left 3 units. This is h=-3 since 1+-3 = -2.