Since the x's for each one are going up by the same number, you are looking for a column of y's to either by going up by the same number or down by the same number.

The first table has a column of y's that look like this: 1/2 , 1 , 1 1/2, 2

This is actually going up for 1/2 each time.

This table shows a linear function.

8 0

2 years ago

When 5√20 is written in simplest radical form , the result is k√5 what is the value of K

Vladimir [108]

Answer:

Step-by-step explanation:

√20 can be rewritten as the product of two radicals: √4√5,

and √4 = 2.

Thus, 5√20 = 5(2)√5 = 10√5. Thus, B: 10 is correct; k = 10.

7 0

2 years ago

F(x)=x-1/x^2-x-6 which is the graph of

hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

$f\left(x\right)=x-\frac{1}{x^2}-x-6$

$x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:$

$\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0$

$-\frac{1}{x^2}-6=0$

$-1-6x^2=0$

$\mathrm{No\:Solution\:for}\:x\in \mathbb{R}$

$\mathrm{No\:x-axis\:interception\:points}$

$y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:$

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

$\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}$