It’s a. vertex is the lowest or highest point so (1,-8) x-intercepts is where the parabola hits the x axis so (-1,0) and (3,0)
The answer is right below:
A word to the wise: It's <span> f(x)=125(0.9)^x, where ^ represents exponentiation.
In this case the ave. value over the interval [11, 15] is
125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
15 - 11 = (31.25) [ 0.2059 - 0.3138 ] = a negative result
= (31.25)(-0.1079) = -3.372 (av. r. of c.
over the interval [11,15] )
Do the same thing for the time interval [1,5]. Then compare the two rates of change.</span>
Answer:
Last one: 5x - 3√y + 1
Step-by-step explanation:
8x + √1 - √9y - √9x^2
8x + 1 - 3√y - 3x
5x + 1 - 3√y
5x - 3√y + 1
CAN YOU PLEASE MARK MY ANSWER BRANLIEST
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
This means that Purple #1 is <u>a redder</u> shade of purple than Purple #2.
Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
Step-by-step explanation:
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
- Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2
- Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.
- Hence, Purple #1 is <u>a redder</u> shade of purple than Purple #2.
- From the above explanation, Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
