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konstantin123 [22]
2 years ago
15

Question 1 of 5

Mathematics
2 answers:
Sati [7]2 years ago
8 0
The answer would be (B) y=2x−3
thank comment
Murljashka [212]2 years ago
3 0

Answer:

the equation would be b. y=2x-3.

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WHAT IS THE SOLUTION TO THIS EQUATION<br> 1. 8x - 5(x- 3)= 18
marysya [2.9K]

Answer:

x = 1

Step-by-step explanation:

8x - 5(x - 3) = 18

8x - 5x + 15 = 18   <em>[Expand the brackets]</em>

3x = 3   <em>[Separate variables and constants]</em>

<u>x = 1</u>

5 0
3 years ago
Read 2 more answers
Help me please!!!<br> Sad face sad sad sad please helpppp
Romashka-Z-Leto [24]
It is Parallelograms !!
6 0
3 years ago
PLEASE ANSWER AS SOON AS POSSIBLE!
Tcecarenko [31]
The y- intercept has to be a point in the line where x is 0. Which means that in this case it would be -4.
To find the slope, use the formula: rise over run —> y2 - y1/x2 - x1
Choose any two coordinates and plug them in. Then simplify. Let me know if you have any questions by commenting:)
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6 0
3 years ago
There are two boxes containing only black and orange pens.
cestrela7 [59]

Answer:

Event 3 -> Event 1 -> Event 4 -> Event 2

Step-by-step explanation:

The probability of choosing a certain pen is the number of that pen in the box over the total number of pens in the box.

So we have that:

Event 1: We have 4 black pen and 20 total pens, so P = 4 / 20 = 1 / 5

Event 2: All pens are black or orange so the probability is 1.

Event 3: We don't have white pens, so the probability is 0.

Event 4: We have 2 black pen and 5 total pens, so P = 2 / 5

Listing from least likely to most likely, we have:

Event 3 -> Event 1 -> Event 4 -> Event 2

3 0
3 years ago
Jenna is at a fair with four friends. They all want to ride the roller coaster, but only three people can fit in a car. How many
pav-90 [236]

Answer:

They can make 10 different groups of three.

Step-by-step explanation:

The order in which the people are in the car is not important, so we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many different groups of three can the five of them make?

Combinations of 3 from a set of 5. So

C_{5,3} = \frac{5!}{3!(5-3)!} = 10

They can make 10 different groups of three.

6 0
2 years ago
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