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3 years ago

Yoga lessons cost $5 per lesson if Kylie enrolls in the health club for a

Mathematics

1 answer:

Ludmilka [50]3 years ago

8 0

Answer:

For one year the fee would be,

C = $120 + $5l

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

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Can i have help please?

alexandr1967 [171]

The means and medians are not  the same.

3 0

4 years ago

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Part of arianna’s earnings are based on a 5% commission rate. At the end of the day arianna earned 14.98 in commission. How much

Katarina [22]

Arianna sold for $ 299.6

Solution:

Given that, Part of Arianna’s earnings are based on a 5% commission rate

At the end of the day arianna earned 14.98 in commission

Therefore,

Commission earned = $ 14.98

Commission rate = 5 %

Let "x" be the amount that Arianna sell that day

Therefore, according to question,

5 % of amount earned = 14.98

5 % of "x" = 14.98

Solve the above equation for "x"

$5 \% \times x = 14.98\\\\\frac{5}{100} \times x = 14.98\\\\5x = 14.98 \times 100\\\\5x = 1498\\\\Divide\ both\ sides\ of\ equation\ by\ 5\\\\x = 299.6$

Thus arianna sold for $ 299.6

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3 years ago

Which of the following is the most appropriate unit.to describe the rate at which a person reads

BaLLatris [955]

The answer is a words per minute, because the independent quantity is the words

8 0

3 years ago

Help with this plz bc I don’t want to get I trouble by my teacher

aksik [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

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The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

3 years ago